PQ is a chord of a circle with centre O and PT is a tangent. If angle QPT is eqal to 60 degree, find angle PRQ
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Given, PQ is a chord of a circle with center O. Also, ∠QPT = 60°. let x be the point on the tangent PT.
Now, ∠QPT + ∠QPX = 180° [Linear pair]
⇒ ∠QPX = 180° - ∠QPT = 180° - 60° = 120°
Again, ∠QPX = ∠PRQ [Alternate segment theorem]
⇒ ∠PRQ = 120°
Now, ∠QPT + ∠QPX = 180° [Linear pair]
⇒ ∠QPX = 180° - ∠QPT = 180° - 60° = 120°
Again, ∠QPX = ∠PRQ [Alternate segment theorem]
⇒ ∠PRQ = 120°
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