Math, asked by nigamsahoo02, 11 months ago

PQ is a tangent drawn at a point P to a circle with centre O. OQ intersects the circle at R such that OR=RQ. If PQ = 3√3cm, find the radius of the circle .

Answers

Answered by amitnrw
2

Given : PQ is a tangent drawn at a point P to a circle with centre O

OQ intersects the circle at R such that OR=RQ

PQ = 3√3cm

To Find   :  the radius of the circle

Solution:

OR = RQ

OQ = OR + RQ

=> OQ = OR + OR

=> OQ = 2OR

OR = OP ( Radius)

PQ is tangent

=> PQ² + OP² =  OQ²

PQ = 3√3

OQ = 2OP

=> (3√3)²  + OP² = (2OP)²

=> 18 + OP² = 4OP²

=> 3OP² = 18

=>  OP² = 6

=> OP = √6

radius of the circle .  =   √6

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