Question

PQ is a tangent drawn from a point P to a circle with center O and QOR is a diameter of circle such that angle POR =120°.find angle OPQ​

Answer 1

Answer:

∠QOP + ∠POR = 180° ∠QOP + 120° = 180° ∠QOP = 180° - 120° ∠QOP = 60° In ΔPOQ ∠QOP + ∠OPQ + ∠PQO = 180° 60° + ∠OPQ + 90° = 180° 150° + ∠OPQ = 180° ∠OPQ = 180° - 150° ∠OPQ = 30°