Question

PQ is a tangent to a circle with centre O at point P. If ∆OPQ is an isosceles

triangle, then find ∠OQP.​

Answer 1

Answer:

PQ is a tangent to a circle with centre O at the point P. If ΔOPQ is an isosceles triangle, then ∠OQP is equal to (a) 30o (b) 45o (c) 60o (d) 90oRead more on Sarthaks.com - https://www.sarthaks.com/158564/pq-tangent-circle-with-centre-the-point-if-opq-is-an-isosceles-triangle-then-oqp-is-equal

Answer 2

Answer:

45°

Step-by-step explanation:

We know that the radius and tangent are perpendicular at their point of contact Now, In isosceles right triangle POQ

angle a + angle b + angle c= 180°

angle = 45°