devide polynomial x^3+1by x+1
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☞ ᴡᴇ ʜᴀᴠᴇ x³+1 = (x+1) (x²−x+1).
ɴᴏᴡ,
➝ (x²−x+1).
➟ sᴏ ᴡʜᴇɴ x³ +1 ɪs ᴅɪᴠɪᴅᴇᴅ ʙʏ (x+1)
ᴛʜᴇɴ ᴛʜᴇ ϙᴜᴏᴛɪᴇɴᴛ ʙᴇ x²−x+1 ᴀɴᴅ ᴛʜᴇ ʀᴇᴍᴀɪɴᴅᴇʀ ᴡɪʟʟ ʙᴇ 0
[ sɪɴᴄᴇ x³+1 ɪs ᴘᴇʀғᴇᴄᴛʟʏ ᴅɪᴠɪsɪʙʟᴇ ʙʏ (x+1)].
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