Question

PQ is chord of length 6 cm of the circle of radius 6 cm. TP and TQ are tangents to the circle at points P and Q respectively. Find Angle PTQ.

Answer 1

take center of circle as O
join OP,OQ
PQR forms a triangle
so now, OP=OQ=PQ
therefore it is an equilateral triangle
angle POQ=60
angle POQ+angle PTQ=180
therefore angle PTQ=120

Answer 2

Answer:The value of angle PTQ or angle T is 120 degree.

Step-by-step explanation:

PQ=6cm,OP=OQ=6cm

PQ=OP=OQ

Angle POQ=60 degree (angle of equilateral triangle)

Angle P=Angle Q= 90 degree(radius perpendicular to tangent)

Therefore Angle T=90+90+60=360 degree

(angle sum property)

Angle T = 120 degree.