Question

PQ is parallel to side YZ of triangle XYZ.RY||CD and SZ||ST meet extended PQ in S and S respectively. Show that ar (XRY)=ar(XZS)

Answer 1

Give RY//XZ, XY//SZ and YZ// RS

In triangle RXY and triangle ZXY

XY = XY (common)

Angle RXY = Angle ZYX
Angle RYX = Angle ZXY (alternative angles)

Triangle RXY = Triangle ZXY
or Triangle RXY = Triangle ZXY

Answer 2

Given that
RY||XZ, XY||SZ and YZ|| RS

In triangRXY and traingZXY

then

XY =XY

angle RXY = Angle ZYX and
Angle RXY =Angle ZXY (alternate interior angle )


TraingRXY = Traing ZXY

I hope this helps