Question

PQ is perpendicular to PS,PQ is parallel to SR ,angle SQR=25degrees,angle QRT=60 degrees.find X and Y​

Answer 1

Answer:

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yashu114

yashu114

30.03.2018

Math

Secondary School

+5 pts

Answered

in figure PQ perpendicular to PS and PQ parallel to SR angle SQR=28° and angle QRT=65° . find the value of X and Y

2

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Answers

PratyushM

PratyushM Ambitious

Find x by alternate angle property when 180-28-115

find y by 180 -x+90

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yashu114

pls solve and show

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Hello mate ☺

____________________________

Solution-

It is given that PQ∥SR. Therefore, ∠QRT=∠PQR (Alternate Interior Angles)

⇒65°=x+28°

⇒x=65°−28°=37°

In ∆PQS, we have

x+y+∠SPQ=180° (Sum of three angles of a triangle =180°)

⇒37°+y+90°=180° ( It is given that ∠SPQ=90°)

⇒y=180°-37°−90°=53°

Therefore, x=37° and y=53°

I hope, this will help you.☺

Thank you_____

Step-by-step explanation:

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Answer 2

Answer:

given=<SQR=25 and <QTR=60

Step-by-step explanation:

we know that,

PQ//ST by the alternate interior angle <QRT=<PQR

<PQR=60

so, sum of <PQS and SQR is <PQR

then, <PQS + <SQR = <PQR

x + 25 =60

x =60 - 25

x =35

now,

in PQS sum of all angles is 180

<SPQ + <PQS + <QSP = 180

90 + 35 + y = 180

125 + y = 180

y = 180 - 125

y = 55

hence the value of x and y is 35 and 55

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