Question

pq is tangent at c to circle with centre at o Ab is diameter &angle cab =30°​

Answer 1

Answer:

Given: PQ is a tangent. AB is a diameter, ∠CAB=30  

o

 

To find: ∠PCA=?

In ΔAOC,

∠CAB=∠OCA (Angles opposite to equal sides are equal)

So, ∠CAB=30  

o

=∠OCA

Since OC⊥PQ (Tangent is perpendicular to the radius at point of contact)

∠PCO=90  

o

 

∠OCA+∠PCA=90  

o

 

30  

o

+∠PCA=90  

o

 

∠PCA=90  

o

−30  

o

 

Therefore, ∠PCA=60  

o

Step-by-step explanation: