Question

PQ is tangent to a circle with centre at O,at point B if angle of AOB is 100 then Angle ABP is equal to?

Answer 1

Answer: A) 50

Step-by-step explanation: see I'm not sure but the way I got that answer was like angle oab = angle oba.

And then,

100 + 2oab = 180 (angle sum property)

2oab = 180-100

Oab = 80/2

Oab = 40 = oba

Now pq is tangent so on is perpendicular , which means that it is 90 degrees.

So abp = 90 - 40

= 50

This is how I got my answer.

Not sure though :)