pq prallel sr, sp prependicular pq, pq= 60cm, sr= 36 cm and qr= 25 cm. find the area of quadrilateral pqrs
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draw a perpendicular from R to PQ . RT_| PQ.T is on PQ
RTQ is a right angled triangle
TQ=60-36=24
RQ=25
RT=sqrt(25^2-24^2)=7
area of PQRS=(60+36)/2 * 7=48*7=336
RTQ is a right angled triangle
TQ=60-36=24
RQ=25
RT=sqrt(25^2-24^2)=7
area of PQRS=(60+36)/2 * 7=48*7=336
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