Question

PQ = QR = l rod is rotating in a uniform magnetic field as shown about point P. Potential difference between Q and R is
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Answer 1

Answer:

please provide the diagram

Answer 2

Given:

PQ = PR = l rod is rotating in a uniform magnetic field as shown about point P.

To find:

Potential difference between Q and R.

Calculation:

General expression of of induced EMF in a rod of legth "r" rotating in a uniform magnetic field is given as follows:

$\boxed{ \rm{E = \dfrac{1}{2} B \omega {r}^{2} }}$

Now , induced EMF in part PR be E1.

$\therefore \: \rm{E1 = \dfrac{1}{2} B \omega {( l) }^{2} }$

Again , induced EMF in part PQ be E2.

$\therefore \: \rm{E2 = \dfrac{1}{2} B \omega {( l) }^{2} }$

Now , potential difference between Q and R

$\rm{E = E1 - E2 }$

$= > \: \rm{E = \dfrac{1}{2} B \omega {( l) }^{2} - \dfrac{1}{2} B \omega {(l)}^{2} }$

$= > \: \rm{E = 0 \: volt}$

So, final answer is:

$\boxed{ \: \bf{E = 0 \: volt}}$