Question

pqa=(3p+q)^2-(3p-q)^2, find value of a?

Answer 1

Given,
$pqa = ({3p + q})^{2} - ( {3p - q})^{2}$
because,
${a}^{2} - {b}^{2} = (a + b)(a - b)$
here
$a = 3p + q \\ b = 3p - q$
so
$a + b = (3p +q) + (3p - q) \\ a + b = 6p$
similarly,
$a - b = (3p + q) - (3p - q) \\ a - b = 2q$
putting these values,

we get
$pqa = (6p)(2q) \\ pqa = 12pq \\ \: \: \: \: \: a = 12pq \div pq \\ \: \: \: \: \: \:a = 12 \: answer$

Answer 2

U can have 'a' in the places of x.....