∆PQR ∠ > ∠ and M is a point on QR such that PM is the bisector of∠.If the perpendicular from P
on QR meets QR at N.Prove that ∠ = 1/2(∠ − ∠)
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Given: Δ PQR, PM is the bisector of ∠ QPR such that ∠ QPM = ∠ MPR and PN ^ QR.To prove: ∠ NPM = (∠ Q -∠ R)Proof: In Δ NPM, ∠ PNM = 90° ...
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