Pqr is a right angled triangle,right angled at p.Ps is perpendicular to qr.Ifpq=10 cm, qr=24cm andpr=26 cm .Find length of ps
nitinnayan441:
sorry my solution is wrong
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we know that area of right triangle= (1/2×product of its legs)sq.units
first we find area of given triangle
Area of right triangle =(1/2×product of its legs)sq.units
:(1/2×26×10)cm sq.
:(13×10)cm sq.
:130 cm sq.
Now ps pependicular to qr
then
ps is height ,let ps be h cm
we know that area of triangle =(1/2×b×h)sq.units
:(1/2×24×h)cm sq.
(12h)cm sq.
then
12h=130
:h=130/12
first we find area of given triangle
Area of right triangle =(1/2×product of its legs)sq.units
:(1/2×26×10)cm sq.
:(13×10)cm sq.
:130 cm sq.
Now ps pependicular to qr
then
ps is height ,let ps be h cm
we know that area of triangle =(1/2×b×h)sq.units
:(1/2×24×h)cm sq.
(12h)cm sq.
then
12h=130
:h=130/12
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