PQR is a triangle in which PQ = PR. S is any point on on the side PQ. Through S, a line is drawn parallel to QR intersecting PR at T. Prove that PS = PT
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Since PQ = PR
and ST is parallet to QR
Therefore by Side Angle Side congruence
ΔPQR ~ΔPST
hence PS=PT
and ST is parallet to QR
Therefore by Side Angle Side congruence
ΔPQR ~ΔPST
hence PS=PT
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Answer:
In ∆ PQR , we have,
Step-by-step explanation:
PQ = PR
<R= <Q
Now, ST||QR
<PST = < PQR and <PTS = < PRQ { corresponding angles are equal}
<PST = < Q and <PTS= < R
<PST = < PTS
PT = PS. proved
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