PQR IS A TRIANGLE, RIGHT ANGELD AT P. IF PQ =10 CM and PR =24 CM FIND QR
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Answer to yr question ...
According to Pythagoras theorem ... QR^2 = PQ ^2 + PR^2
QR^2 = (10)^2 + (24)^2
QR^2 = 100 + 576
QR^2 = 676
QR = √676
QR = 26 cm
According to Pythagoras theorem ... QR^2 = PQ ^2 + PR^2
QR^2 = (10)^2 + (24)^2
QR^2 = 100 + 576
QR^2 = 676
QR = √676
QR = 26 cm
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