Question

pqr is a triangle right angled at p if PQ is equal to 10 cm and PR is equal to 24 cm find QR

Answer 1

By PGT
${24}^{2} + {10}^{2} = {qr }^{2} \\ {qr}^{2} = 576 + 100 \\ {qr }^{2} = 676 \\ {qr}^{} = 26$

Answer 2

Answer:

Refer to the attachment above. ⬆️

hope it helps!!