Question

pqr is an equilateral triangle with it coordinates of q and r as - 2,0 and 2,0 respectively find the coordinates of vertex p​

Answer 1

Answer:

Length of given side = 4 units. As it is equilateral triangle, all sides should be equal. So, length of remaining two sides is also 4 units.

Let, P= (x,y)

Then,

(x+2)² + y² = (x-2)² + y²

→ x= 0

Now,

Length of side = 4 units.

So,

(x+2)² + y² = 4²

→ As x = 0, y = 2√3

So, point P = (0, 2√3)