PQR is an isosceles triangle,PQ=QR. RQ is produced to M. PM is perpendicular to QR. Prove that PR^2=2QR*MR
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Secondary School Math 5 points
PQR is a triangle in which QM perpendicular to PR and PR square - PQ square = QR square. Prove that QM square = PM*MR
Ask for details Follow Report by Ajayhudge9048 28.12.2017
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Geekydude121
Geekydude121 Virtuoso
Given that
PQR is a triangle and QM is perpendicular on PR
Also,
PR^2 - PQ^2 = QR^2
Now in traingle QMR
QR^2 = QM^2+MR^2
Thus fro above two equations for QR
We get
PR^2 - PQ^2 = QM^2 + MR^2
QM^2 = PR^2 - PQ^2 -MR^2
QM^2 = (PM+MR)^2 - PQ^2 - MR^2
QM^2 = PM^2 + MR^2 + 2PM*MR - PQ^2 - MR^2
QM^2 = PM^2 + 2 PM^MR - PQ^2
QM^2 = PQ^2 - QM^2 + 2PM*MR - PQ^2
thus, 2QM^2 = 2 PM * MR
Hence prooved
DO IT IN THE SAME WAY