∆PQR is an isosceles triangle with PQ=PR and PM is one of its altitude
a) is ∆PMQ = ∆PMR?
b) is Q=R?
c) is QM=RM?
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Step-by-step explanation:
PQ = PR (given)
angle PMQ = angle PMR (90°)
PM = PM ( common )
therefore, triangle PQM is congruent to triangle PRM (RHS congruency)
angle Q = angle R ( CPCT)
QM = RM ( CPCT )
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