PQRS in a quadrilateral with angle Q= 65° and angle S=105°. If angle P and angle R are the ratio 3:7, find angle P and angle Reply
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Answer:
let angle p = 3x
angle r=7x
therefore sum of angles of quadrilateral is 360
65+105+7x+3x=360
170+10x=360
10x=360-170
x=190/10
x=19
therefore angle p= 3× 19= 57
angle q=7×19= 153
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