Question

PQRS in which PQ = 6 cm, QR=4 cm, ΔP= 45°, ΔQ = 115º and ΔS = 95°. [Hint. Find ΔR using ΔR = 360° - (ΔP + ΔQ + ΔS)].

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Answer 1

Answer:

sum of a quadrilateral = 360°

∆P + ∆Q + ∆S = 225°

∆R = 360° - 225°

= 135°

Step-by-step explanation:

construction;

: draw a quadrilateral and name it PQRS

: Mark the angle that given