PQRS is a cyclic Quadrilateral PQ = PS and QR = QS. If 4 QRS = 70°,find the angles marked a, x and y.
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Step-by-step explanation:
⇒ In figure, PQRS is a cyclic quadrilateral.
⇒ The sides PS and QR are produced to meet at B.
⇒ ∠QPB=∠QPR+∠RPS=40
o
+35
o
=75
o
---- ( 1 )
⇒ In △PBQ
⇒ ∠PBQ+∠BQP+∠QPB=180
o
[ Sum of angles of triangle is 180
o
]
⇒ 30
o
+∠BQP+∠75
o
=180
o
⇒ ∠BQP=180
o
−105
o
∴ ∠BQP=75
o
--- ( 2 )
∴ ∠QPB=∠BQP [ From ( 1 ) and ( 2 ) ]
∴ △PBQ is isosceles triangle.
∴ PB=QB [ Sides of isosceles triangle ]
hope it's helpfull
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