Math, asked by avishkamittal21, 2 months ago

PQRS is a cyclic quadrilateral such that side PQ is the diameter of the circle and anglePSR = 115°. The value of angleOPR is​

Answers

Answered by amitnrw
0

Given : PQRS is a cyclic quadrilateral such that side PQ is the diameter of the circle  .  ∠PSR = 115°.

To Find :  ∠OPR

Solution:

PQRS is a cyclic quadrilateral

Sum of opposite angles in   cyclic quadrilateral = 180°

∠PSR  + ∠PQR = 180°

∠PSR = 115°  

=> 115°   + ∠PQR = 180°

=> ∠PQR =65°

PQ is Diameter

∠PRQ = 90°

in  ΔPQR

∠PRQ + ∠PQR + ∠QPR = 180°

=> 90° + 65° +  ∠QPR = 180°

=> ∠QPR = 25°

PQ is Diameter hence O lies on PQ

=> ∠OPR  = ∠QPR

=> ∠OPR  = 25°

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