Question

PQRS is a parallelogram (Fig 11.23). QM is the height from Q to SR and QN is the height from Q to PS. If SR = 12 cm and QM = 7.6 cm. Find:
(a) The area of the parallelogram PQRS (b) QN, if PS = 8 cm
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Answer 1

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(a) Given, Base = 12 cm, Height = 7.6 cm

Area of the parallelogram PQRS = Base ×Height

=12cm×7.6cm

=91.2sq cm

(b) Given; Base PS = 8cm

Area = Base * Height

=> 91.2 = 8 * Height

=> Height = 11.4 cm

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Answer 2

$\huge\mathfrak{\underline{Correct\: question}}$

PQRS is a parallelogram (Fig 11.23). QM is the height from Q to SR and QN is the height from Q to PS. If SR = 12 cm and QM = 7.6 cm.

Find: (a) The area of the parallelogram PQRS (b) QN, if PS = 8 cm.

_____________________________

Given that:-

• PQRS is a parallelogram

• QM is the height from Q to SR and QN is the height from Q to PS.

• SR = 12 cm and QM = 7.6 cm.

To find:-

• The area of the parallelogram PQRS

• QN, if PS = 8 cm

Answer:-

$\bold{STEP-BY-STEP-EXPLANATION}$

From the question it is given that,

SR = 12 cm, QM = 7.6 cm

(a) We know that,

Area of the parallelogram = $\boxed{base × height}$

= SR × QM

= 12 × 7.6

= 91.2 cm2

(b) Area of the parallelogram = $\boxed{base × height}$

91.2 = PS × QN

91.2 = 8 × QN

QN = 91.2/8

QN = 11.4 cm

Therefore, area of parallelogram (PQRS) = 91.2cm^2, and QN = 11.4cm

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