Question

Pqrs is a parallelogram where pq is parallel to rs. Prove that ar(sor) = ar(pqo)

Answer 1

First draw a diagram to understand my solution.

Join P,R and S,Q. PR and QS intersect at point O.

In triangle PQO and SOR,

PO=OR (since the diagonals are equally bisected in a parallelogram)

QO=OS

AND PQ=RS

So, triangle PQO and SOR are congruent

So, the area of triangle PQO and SOR is same.