Question

Pqrs is a rectangle in which the diagonals pr and qs intersect each other at point o. if op= 2x+7 and oq = 5x +4. find the value of x.

Answer 1

OP = OR = OQ = OS. (properity of diagonals of a rect.)
Hence:-
2x + 7 = 5x + 4 (as OP and OQ were proven equal before)
=> 5x - 2x = 7 - 4
=> 3x = 3
=> x = (3/3)
=> x = 1
Hope it helps,

Answer 2

Given : Pqrs is a rectangle in which the diagonals pr and qs intersect each other at point o  

op= 2x+7 and oq = 5x +4

To Find : Value of x

Solution:

Diagonals of rectangle are equal and they bisect each other

=> OP = OQ = OR = OQ

OP = 2x + 7

OQ  = 5x  4

5x  + 4 = 2x + 7

3x = 3

=> x = 1

Value of x is 1

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