PQRS is a rectangle with dimensions 28m by 20m. POQ is a triangle such that O is the point of intersection of the diagonals. Find the area of the shaded region.
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Answered by
72
Rectangle pqrs and triangle poq have same base PQ and lie between the parallel SR and PQ
so, ar(POQ)=1/4ar(PQRS)
area of rectangle =l.b
l=20m
b= 28m
=20m.28m
=560sq.m
1/4 ar(PQRS) =1/4.560
=140
area of the shaded region = total rectangle area - triangle area
=560-140
=420
therefore area of shaded region is equals to 420 metre square
Answered by
19
Answer:
Area of rectangle = l×b
= 20×28
= 560m^2
= 1/4×560m
= 140m
= 560-140m
= 420m^2
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