pqrs is a rhombus if psq =50degree then find the angles of a rhombus
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Given: PQRS is a rhombus
PQS= 50*
to find - angle P,Q,R,S
i.e. PQS=PSQ(adjacent sides of a rhombus are equal)
in triangle PSQ
PSQ+PSQ+P=180*
2PSQ+P=180*
100+P=180*
P=80*
also ,P=R=80*
angle P+Q=180*(when two lines are parallel and cut by a transversal then angles formed are supplementary)
so angle Q= 180- P
Q=180-80=100*
also Q=S=100*
So , Angle P and R= 80*
and Q and S = 100*
_______________________________________________Thanks______
PQS= 50*
to find - angle P,Q,R,S
i.e. PQS=PSQ(adjacent sides of a rhombus are equal)
in triangle PSQ
PSQ+PSQ+P=180*
2PSQ+P=180*
100+P=180*
P=80*
also ,P=R=80*
angle P+Q=180*(when two lines are parallel and cut by a transversal then angles formed are supplementary)
so angle Q= 180- P
Q=180-80=100*
also Q=S=100*
So , Angle P and R= 80*
and Q and S = 100*
_______________________________________________Thanks______
anusha19:
but i dont understand in a better way
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34
Hare Krishna
hope this answer will help you if you find it correct please MaRK me as brainliest
hope this answer will help you if you find it correct please MaRK me as brainliest
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