Math, asked by arjunsingh9950, 10 months ago

Pqrs is a rhombus pq=12cm,qs=16 cm, find the side of the rhombous

Answers

Answered by kmpartha
25

Answer:

The side of the rhombus is 10 cm only if the question was PR=12cm.

Step-by-step explanation:

Let the intersection of the diagonals of the rhombus be 'O'.

PR=12cm so PO=6cm

It is one of the properties of the rhombus that the diagonals act as perpendicular bisectors for each other which is why PO is half of PR.

This also applies for QS.

QS=16cm so QO=8cm

The angle between the PO and QO is 90 degrees.

[This is also another property of the rhombus]

Therefore POQ is a right angled triangle.

PO=6cm ,QO=8cm , PQ=hypotenuse=(6^2 + 8^2)^ 1/2

                                                            =(36+64)^1/2

                                                             =100^1/2

                                                             =10 cm

All sides of the rhombus are equal.

Therefore each side is 10cm.

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