PQRS is a rhombus. the diagonals are 8cm and 6cm respectively. find its perimeter
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Solution :-
Given - PQRS is a rhombus and we know that all four sides of a rhombus are of equal length.
And, In Δ POQ
PQ is hypotenuse, OP is base and OQ is perpendicular.
Using Pythagoras Theorem -
⇒ (PQ)² = (OP)² + (OQ)²
⇒ (PQ)² = (3)² + (4)²
⇒ (PQ)² = 9 + 16
⇒ (PQ)² = 25
⇒ PQ = √25
⇒ PQ = 5 cm
So, length of each side of the given rhombus is 5 cm.
Perimeter of rhombus = 4 × side
⇒ 4 × 5
= 20 cm
So, perimeter of the rhombus PQRS is 20 cm.
Answer.
Given - PQRS is a rhombus and we know that all four sides of a rhombus are of equal length.
And, In Δ POQ
PQ is hypotenuse, OP is base and OQ is perpendicular.
Using Pythagoras Theorem -
⇒ (PQ)² = (OP)² + (OQ)²
⇒ (PQ)² = (3)² + (4)²
⇒ (PQ)² = 9 + 16
⇒ (PQ)² = 25
⇒ PQ = √25
⇒ PQ = 5 cm
So, length of each side of the given rhombus is 5 cm.
Perimeter of rhombus = 4 × side
⇒ 4 × 5
= 20 cm
So, perimeter of the rhombus PQRS is 20 cm.
Answer.
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