Question

PQRS is a square.
if PQ=(2/3x+1)cm and QR=9cm,what is the value of x

Answer 1

$\bold{\underline{Solution:}}$

As it is given that PQRS is a square. So according to the properties of square, the measure of each side are equal in a SQUARE.

$\bold{\boxed{A.T.Q}}$

$\frac{2}{3} x + 1 = 9 \\ \\ \frac{2x }{3} = 9 - 1\\ \\ \frac{2x}{3} = 8 \\ \\ 2x = 8 \times 3 \\ 2x = 24 \\ \\ x = \frac{24}{2} = 12$

Hence, the value of x = 12.

$\bold{\underline{Verification}}$

$\frac{2}{3} x + 1 = 9 \\ \\ \frac{2}{3} \times 12 + 1 = 9 \\ \\ 4 \times 2 + 1 = 9 \\ \\ 8 + 1 = 9 \\ \\ 9 = 9$

Hence, the value of x is 12.

$\bold{\underline{Thank you!!}}$

Answer 2

PQ=(2/3x+1),QR=9cm
PQRS IS A SQUARE
PQ=QR=RS=PS
PQ=QR
2/3x+1=9
2/3x=8
2/8=3x
1/4=3x
x=1/12
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