Math, asked by saigigunniipser, 1 year ago

PQRS is a square lawn with side PQ=42 m .two circular flower beds are there on the sides PS and QR with centre O,the intersection of its diagonal.fnd the area of the two flower beds.shaded part.NO LINKS PLZ I NEED ANSWER OR ELSE I WOULD POST IT AGAIN

Answers

Answered by ShlokPatel

2

area of flower beds = 2(area of one flower beds)
=2(1/2πr²)
=2[(1/2)(22/7)(21*21)]
=(22/7)21x21
=1386 cm²

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