Question

PQRS is a trapezium such that PQ || RS, ∠P : ∠S = 3 : 7, ∠Q : ∠R = 5 : 7. Find the angles of the
trapezium

Answer 1

Answer:

Step-by-step explanation:

Let ∠P be 3x, ∠S be 7x, ∠Q be 5 x and ∠R be 7x

now, ∠P+∠Q+∠R+∠S= 360°

=> 3x+5x+7x+7x= 360°

=> 22x= 360°

=> x= 360°/22 = 16.37°

Therefore, ∠P= 3X16.36= 49.1°

∠Q= 5X16.36 = 81.8°

∠R= 7X16.36 = 114.55°

∠S= 7X16.36 = 114.55°