PQRTS is a pentagon. A line through T meets QR produced in U such that SR || UT. Show that ar ( PSUQ) =ar (PQRTS).
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Given : ABCDE is a Pentagon.
Construction : join AF anf BC
Proof :
(1)
Since triangles ACD
and triangle ACF
are on the same base AC and between the same parallels AC and BF. So,
ar ( triangle ACD)= ar (triangle ACF)
hence proved.
(2)
now
ar ( triangle ACD)= ar ( triangle ACF)
adding ar (ACDE) both sides we get,
ar( triangle ACB) +ar (ACDE)= ar (triangle ACF)+
ar (ACDE).
=> ar ( ABCDE)= ar(AEDF)
Hence Proved.
Construction : join AF anf BC
Proof :
(1)
Since triangles ACD
and triangle ACF
are on the same base AC and between the same parallels AC and BF. So,
ar ( triangle ACD)= ar (triangle ACF)
hence proved.
(2)
now
ar ( triangle ACD)= ar ( triangle ACF)
adding ar (ACDE) both sides we get,
ar( triangle ACB) +ar (ACDE)= ar (triangle ACF)+
ar (ACDE).
=> ar ( ABCDE)= ar(AEDF)
Hence Proved.
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