Question

Pqx ^2 - (p+q)^2x+(p+q) ^2=0

Answer 1

Answer:

pqx^2-(p^2+q^2)x+pq=0

pqx^2-p^2x-q^2x+pq=0

px (qx-p)-9 (9x-p)=0

(qx-p)(px-q)=0

x=p/q,q/p