Physics, asked by adarshsingh29102002, 2 months ago

PR
E 3
Id intensity at points outside a 'non-conducting charged sphere.
sphere, the entire charge will lie on the surface and only Eq. (i) will hold.
es just on the surface of the sphere, then r = R. Equations (i) and (ii) now give
1
a
4 πες B2
- suppose that the point P lies inside the
(Fig. 18). We again draw a Gaussian
the same arguments as above the flux
R
"e = E (4 nr 2).
d
, where q' is that part of q which is
radius r (< R).
q'
GAUSSIAN
SURFACE
EO
(Fig. 18)​

Answers

Answered by vasundhrakrishnar
0

Answer:

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