Seg PM and seg PN are congruent chords of a circle with centre C. Show that the ray PC
is the bisector of NPM.
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Answer:
hey here is your proof
pls mark it as brainliest answer
refer the reference diagram uploaded above
Step-by-step explanation:
so consider triangle mcp and triangle ncp
so here pm=pn (given)
also mc=cn (radii of same circle)
also pc=pc (common side)
thus triangle mcp congruent to triangle ncp by S.S S Test
so angle mpc=npc (c.a.c.t)
so now as pc divides angle mcp and ncp
in two equal congruent angles
we can say that pc is bisector of angle mpn
thus ray pc is the bisector of angle mpn
thus proved
hope it helped u a lot
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