Question

prabal deposited rs 5000 in a bank which pays 5 1/2% interest . after three years ,
he withdraws the money and buys an almarih for rs 4,700.how much money is left with him

Answer 1

Answer:

SI =P*T*R/100

=5000*3*11/200

=825

Amount=5000+825=5825

Money left with him 5825-4700=1125

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Answer 2

Answer :

➥ Money left with him = Rs. 1125

Given :

➤ Principal (P) = Rs. 5000

➤ Time (T) = 3 years

➤ Rate (R) = 5½

To Find :

➤ Money left with him = ?

Solution :

As we know that

$\tt{:\implies S.I = \dfrac{P \times R \times T}{100} }$

$\tt{:\implies S.I = \dfrac{50 \cancel{00} \times 5 \frac{1}{2} \times 3}{1 \cancel{00}} }$

$\tt{:\implies S.I = \cancel{50} \times \dfrac{11}{ \cancel{ \: 2 \: }} \times 3 }$

$\tt{:\implies S.I = 25 \times 11 \times 3}$

$\tt{:\implies S.I = 275 \times 3}$

$\bf{:\implies \underline{ \: \: \underline{ \green{ \: \: S.I = 825 \: \: }} \: \: }}$

As we know that

$\tt{:\implies Amount = P+I}$

$\tt{:\implies Amount = 500 + 825}$

$\bf{:\implies \underline{ \: \: \underline{ \green{ \: \: Amount = Rs. \: 5825 \: \: }} \: \: }}$

Now ,

He spent to by almirah at 4700 :

$\tt{: \implies 5825 - 4700}$

$\bf{: \implies \underline{ \: \: \underline{ \purple{ \: \: Rs. \: 1125 \: \: }} \: \: }}$

Hence, the money left with him is Rs. 1125.