Question

Practice set 1.1.
1. Base of a triangle is 9 and height is 5. Base of another triangle is 10 and height is 6. Find the ratio of areas of these triangles. ​

Answer 1

Step-by-step explanation:

To Find :- Ratio of Area of ∆ABC and ∆PQR

♦ Solution :-

\begin{gathered} = \frac{area \: \: of \: \: abc}{area \: \: of \: \: pqr} \\ \\ = \frac{ \frac{1}{2} \times ae \times bc }{ \frac{1}{2} \times pm \times qr } \\ \\ = \frac{ \frac{1}{2} \times 5 \times 9 }{ \frac{1}{2} \times 6 \times 10} \\ \\ = \frac{3}{4} \\ \\ \end{gathered}

=

areaofpqr

areaofabc

=

2

1

×pm×qr

2

1

×ae×bc

=

2

1

×6×10

2

1

×5×9

=

4

3

Hence, Ratio of Area of ∆ABC to ∆PQR is 3:4