Question

Practice set 1.1
• Base of a triangle is 9 and height is 5. Base of another triangle is 10 and height
is 6. Find the ratio of areas of these triangles.
5​

Answer 1

Answer:

Ratio = 3:4

Step-by-step explanation:

In first triangle

b= 9,. h = 5

Ar. = 1/2×b×h = 1/2×9×5 = 22.5

In second triangle

b= 10,. h = 6

Ar.= 1/2×b×h = 1/2×10×6 = 30

Ratio = 22.5/30 = 225/300 = 3/4

Answer 2

✬ Ratio = 3 : 4 ✬

Step-by-step explanation:

Given:

• Measure of base and height of first triangle is 9 & 5 respectively.
• Measure of base and height of second triangle is 10 & 6 respectively.

To Find:

• What is ratio of area of both triangles ?

Solution: Let units be in cm. In first triangle

• Base = 9 cm and Height = 5 cm

As we know that

★ Area of ∆ = 1/2(Base)(Height) ★

$\implies{\rm }$ Area = 1/2(9)(5) cm²

$\implies{\rm }$ Area = 1/2 $\times$ 45 cm²

$\implies{\rm }$ Area = 45/2 cm²

$\implies{\rm }$ Area = 22.5 cm²

So, Area of first ∆ is 22.5 cm².

Now, In second triangle

• Base = 10 cm and Height = 6 cm

$\implies{\rm }$ Area = 1/2(10)(6) cm²

$\implies{\rm }$ Area = 1/2 $\times$ 60 cm²

$\implies{\rm }$ Area = 30 cm²

So, Area of second ∆ is 30 cm².

∴ Ratio of areas =(Ar. of 1st ∆/Ar. of 2nd ∆)

➱ Ratio = 22.5/30

➱ 225/30 $\times$ 10

➱ 225/300

➱ 3 : 4

Hence, Ratio of areas of both triangle is 3 : 4.