Question

Practice Set 1.5
(1) Two numbers differ by 3. The sum of twice the smaller number and thrice
the greater number is 19. Find the numbers.​

Answer 1

Answer:

let the two numbers be x and y such that x> y. so equation 1 is x-y = 3. so x = y + 3. equation 2 will be 2y + 3x = 19. replace the value of x in equation 2.

now we get

2y + 3 (y + 3) = 19

2y + 3y + 9 = 19

5y = 19 - 9

5y = 10

y = 10/5 = 2

so x = 2 + 3 = 5

Ans x = 5 and y = 2