Math, asked by adityaxsingh2020, 2 months ago

Practice Set 47
1. Find the total surface area of cubes having the following side
(i) 3 cm (ii) 5 cm (iii) 7.2 m (iv) 6.8 m (v) 5.5 m​

Answers

Answered by sabareesh61
1

Answer:

x { { { |. <  >  >  >  > 1 \\  \times \frac{?}{?} | }^{?}  \times \frac{?}{?} }^{?} }^{2}  \times \frac{?}{?}  \times \frac{?}{?}  \\  \\  \\  \\ fgg \: v482y \frac{ \frac{ { {yy)y}^{?} }^{?}  \times \frac{?}{?}  \times \frac{?}{?}  \times \frac{?}{?} }{?} }{?}  \times \frac{?}{?}

Answered by saikrishnareddy2015
4

Answer:

Step-by-step explanation:

i. Total surface area of cube = 6l2 = 6 × (3)2  = 6 × 9  = 54 sq. cm.

ii. Total surface area of cube = 6l2  = 6 × 52 = 6 × 25  = 150 sq. cm.  

iii. Total surface area of cube = 6l2 = 6 × (7.2)2 = 6 × 51.84  = 311.04 sq. m.

iv. Total surface area of cube = 6l2 = 6 × (6.8)2 = 6 × 46.24  = 277.44 sq. m.

v. Total surface area of cube = 6l²  = 6 × (5.5)2 = 6 × 30.25  = 181.5 sq. m.

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