Practice set 6.2
erson is standing at a distance of 80m from a church looking at its top-
The angle of elevation is of 45°. Find the height of the church.
A person is
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- A/C question we will get a right triangle say,OBC in which O is the position of man and BC is the height of church at which he is looking
- Now from question we can easily say that OB=80cm and let BC be x also angle BOC=45°
- Now tan45°=BC/OB=1
- on solving it we get the height BC=80cm
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