Pradesh got 30% marks in examination and failed by 6 marks sudhir got 40% marks which are 6 more than minimum marks required to pass find the maximum marks and minimum percentage of marks required to pass
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Let x be the pass mark.y be the total mark.
30y/100+6=x
40y/100-6=x
Equate
30y/100+6=40y/100-6
12=10y/100
y=120 marks.
Total marks are 120.
Pass mark or minimum mark is,
30y/100+6
(30×120/100)+6
36+6=42.
The pass mark is 42.
The maximum and minimum marks respectively are 120 and 42 marks.
30y/100+6=x
40y/100-6=x
Equate
30y/100+6=40y/100-6
12=10y/100
y=120 marks.
Total marks are 120.
Pass mark or minimum mark is,
30y/100+6
(30×120/100)+6
36+6=42.
The pass mark is 42.
The maximum and minimum marks respectively are 120 and 42 marks.
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