Question

Prakash soaked 6 g raisins in water and after 10 hours found that their mass has becomes 9 g determine the percentage of water absorbed by raisins

Answer 1

mass of raisins before soaking = 6g
mass of raisins after soaking = 9g
mass of water soaked = mass of raisins before soaking - mass of raisins after soaking= 9g-6g =3g
percentage of water soaked = mass of water soaked / mass of water before soaking x 100= 3g/6gx100=50%