Pranab himself takes 20 steps to reach to the top
running up an upward-moving escalator, while
Sharad himself takes only 16 steps to do so. If
Pranab can move 50% faster than Sharad, then
find the number of steps in the escalator.
Answers
Answer:
36+50=86
Step-by-step explanation:
20+16=36
then
36+50=86
then there are 86 steps.
Answer: There are 50 steps in the escalator.
Step-by-step explanation:
Given: Number of steps taken by Pranab = 20, and
Number of steps taken by Sharad = 16
Pranab is 50% faster than Sharad
Solution:
Assume the speed of the escalator to be “a” steps per second.
As it is an escalator, distance covered by both Pranab and Sharad will always be same.
Also, since Pranab is 50% faster than Sharad assume speed of Sharad as 100 and Pranab will be 150 (100 + 50).
Case 1:
Distance covered by Pranab = 20 + 150a Eq. 1
Here, 150a is covered by the escalator. (since distance = speed x time)
Case 2:
Distance covered by Sharad = 16 + 100a Eq. 2
Again, 100a is the distance covered by the escalator.
Now, equating both the equations, obtained equation is:
20 + 150a = 30 + 100a
Separating like terms,
150a -100a = 30-20
∴50a = 10
=> a = 1/5
So, total number of steps will be = 20 + 150 (1/5)
= 20 + 30 = 50 steps
Hence total steps are 50.