Math, asked by nilesh1308, 1 year ago

Pranab himself takes 20 steps to reach to the top
running up an upward-moving escalator, while
Sharad himself takes only 16 steps to do so. If
Pranab can move 50% faster than Sharad, then
find the number of steps in the escalator.​

Answers

Answered by AayushiBansal
9

Answer:

36+50=86

Step-by-step explanation:

20+16=36

then

36+50=86

then there are 86 steps.

Answered by heena012131
0

Answer: There are 50 steps in the escalator.

Step-by-step explanation:

Given: Number of steps taken by Pranab = 20, and

Number of steps taken by Sharad = 16

Pranab is 50% faster than Sharad

Solution:

Assume the speed of the escalator to be “a” steps per second.

As it is an escalator, distance covered by both Pranab and Sharad will always be same.

Also, since Pranab is 50% faster than Sharad assume speed of Sharad as 100 and Pranab will be 150 (100 + 50).

Case 1:

Distance covered by Pranab = 20 + 150a        Eq. 1

Here, 150a is covered by the escalator. (since distance = speed x time)

Case 2:

Distance covered by Sharad = 16 + 100a        Eq. 2

Again, 100a is the distance covered by the escalator.

Now, equating both the equations, obtained equation is:

20 + 150a = 30 + 100a

Separating like terms,

150a -100a = 30-20

∴50a = 10

=> a = 1/5

So, total number of steps will be = 20 + 150 (1/5)

= 20 + 30 = 50 steps

Hence total steps are 50.

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