Math, asked by ipsitad230, 1 month ago

Pranay’s father is seven times his age now. Two years later his father will be five times as old as his
son will be. Find their present ages.

Answers

Answered by malli99634
1

Answer:

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Answered by MerlinSanu
4

Answer: Pranav's age is 4 years and fathers age is  28

Step-by-step explanation:  Let age of Pranav be x

                                      Age of Pranav's father = 7x

                               2 years later Pranav's age  = (x + 2)

                  2 years later Pranav's fathers age = 5(x + 2) or 7x + 2

           ∴ 5(x+2) = 7x+2

             5x+10  = 7x+2

              10 - 2  = 7x - 5x

                     8  = 2x

                      x = \frac{8}{2}

                         =4

∴ Pranav's age is 4 years and fathers age is 7 × 4 = 28

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