Question

Prashant left his house at 6:00 a.m. for Gujarat which is 120 km away he stayed for breakfast in between for 15 minutes and reached Gujarat at 8:30 a.m. calculate his average speed​

Answer 1

Answer:

8.42 km/hr.

Step-by-step explanation:

Distance = 120 km

Time = 14 hr 15 min = 14.25 hrs

so, speed = Distance/Time = 120/14.25 km/hr

= 8.42 km/hr.

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Answer 2

Average speed will be 53.33 km/hour

Step-by-step explanation:

It is given that distance of Gujarat from his home is 120 km

So distance d = 120 km

He left the home at 6:00 am and reached Gujarat at 8:30 am

So time taken by him to reach Gujarat = 8:30 - 6:00 = 2.5 hour

He takes a break of 15 minutes

So effective time taken = 2.5 hour - 0.25 hour ( 15 minutes = 0.25 hour ) = 2.25 hour

Average speed is equal to ratio of distance traveled and time taken

So speed will be $average\ speed=\frac{120}{2.25}=53.333km/hour$

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